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3x^2-63x-100=0
a = 3; b = -63; c = -100;
Δ = b2-4ac
Δ = -632-4·3·(-100)
Δ = 5169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-\sqrt{5169}}{2*3}=\frac{63-\sqrt{5169}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+\sqrt{5169}}{2*3}=\frac{63+\sqrt{5169}}{6} $
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